find the HCF and LCM of
1485 and 4356
Answers
Answer :
Given numbers are 1485 and 4356.
The prime factorization of 1485 and 4356 gives:
Here, 3^2× 11 is the smallest power of the common factors 3 and 11.
Therefore, the H.C.F of these two integers = 3 × 3 × 11 = 99
22 × 33× 51 × 112 are the greatest powers of the prime factors 2, 3 and 7 respectively involved in the given numbers.
Now, L.C.M of 1485 and 4356 = 2 × 2 × 3 × 3 × 3 × 5 × 11 × 11 = 65430
LCM=65340 AND HCF=99.
The HCF of 1485 and 4356 will be 99.
The factors of 1485 are :1,3,5,9,11,15,27,33,45,55,99,135,165,297,495,1485.
And the factors of 4356 are:1,2,3,4,6,9,11,12,18,22,33,36,44,66,99,121,132,198,242,363,396,484,726,1089,1452,2178,4356.
And the LCM of 1458 and 4356 is LCM = 2 x 2 x 3 x 3 x 3 x 5 x 11 x 11 = 65340 this done prime factorization.
LCM = 65340.