Question

Find the HCF and LCM of 231 and 273. Also find the product of the HCF and LCM number. Check, how the above product is related to the product 231 × 273.​

Answer 1

Answer:

Since the H.C.F. is 13, we can write

a=13x

b=13y

for any two positive integers x and y.

Given L.C.M. = 273. We can write

13×x×y=273

⟹xy=273/13

xy=21

Given a>13 and b>13 ,

13x>13⟹x>1

13y>13⟹y>1

Now, xy=21

We need to find x and y.

So, factors of 21 are 1,3,7 and 21.

(x,y) can't be (1,21) or (21,1) since x and y should be greater than 1.

Therefore, (x,y) = (3,7) or (7,3)

Thus,

a = 13×3 = 39

b = 13×7 = 91

Thus, (a,b) = (39,91) or (91,39)

Sum of a and b = (a+b) = 39+91 = 130

Answer 2

Answer:

HCF -21 LCM - 3003 this is answer