Math, asked by abrahamaabrama, 3 months ago

find the HCF and LCM of 2x²-5x-3 and x⁴-27 answer​

Answers

Answered by debakishrestha2022
0

Answer:

2x^2-5x-3

=(x-3)(2x+1)

again

x^3-27

=x^3-3^3

=*(*x-3)(x2+3x+3^3)

hcf = x-3

lcm= (x-3)(2x+1)(x^2+3x+3^3)

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