find the HCF and LCM of 306 and 657by prime factorization method
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Answered by
668
Solution :-
H.C.F Of 306 , 657 is
by using prime factorisation method , we get ;
→ 306 = 2 × 3 × 3 × 17
→ 657 = 3 × 3 × 73
Therefore , H.C.F = 3 × 3 = 9 .
We know , Product of two numbers = H.C.F × L.C.M
H.C.F = 9, L.C.M = X
Now, 9 × X = 306 × 657
X = 306 × 657 / 9
So, L.C.M = 22338 Ans..
hopes it helps ^_^
H.C.F Of 306 , 657 is
by using prime factorisation method , we get ;
→ 306 = 2 × 3 × 3 × 17
→ 657 = 3 × 3 × 73
Therefore , H.C.F = 3 × 3 = 9 .
We know , Product of two numbers = H.C.F × L.C.M
H.C.F = 9, L.C.M = X
Now, 9 × X = 306 × 657
X = 306 × 657 / 9
So, L.C.M = 22338 Ans..
hopes it helps ^_^
Answered by
301
Hi there !!
306 = 2 × 3 × 3 × 17
657 = 3 × 3 × 73
Therefore ,
H.C.F = 3 × 3 = 9
306 = 2 × 3 × 3 × 17
657 = 3 × 3 × 73
Therefore ,
H.C.F = 3 × 3 = 9
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