Question

Find the HCF and LCM of 404 and 96 and verify that
HCF(a,b) x LCM(a,b) = a x b.



$Find the HCF and LCM of 404 and 96 and verify thatHCF(a,b) x LCM(a,b) = a x b.$

Answer 1

Answer:

Let a=404 and b=96

Expressing the number as a product of prime number

404=2×2×101

96=2×2×2×2×2×3

∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696

∴ HCF of 404 and 96 is 2×2=4

Now HCF×LCM=4×9696=38784

Product of two given numbers 404×96=38784

Hence HCM×LCM= product of two given numbers.

Answer 2

Answer:

dhdhdjjdjdjdjdjdjdjdjdj

hdhdhhd

bshshs

shhsshcf