Math, asked by SUPERMANSIVARAJKUMAR, 2 months ago

find the HCF and LCM of 404 and 96 and verify that HCF×LCM= Product of two numbers​

Answers

Answered by vishalbengani07
2

Answer:

Let a=404 and b=96

Expressing the number as a product of prime number

404=2×2×101

96=2×2×2×2×2×3

∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696

∴ HCF of 404 and 96 is 2×2=4

Now HCF×LCM=4×9696=38784

Product of two given numbers 404×96=38784

Hence HCM×LCM= product of two given numbers.

Step-by-step explanation:

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Answered by hakimpurmcs
1

Answer:

let a= 404 and b=96

expressing the number as a product of prime no.

404= 2×2×101

96= 2×2×2×2×2×3

therefore, LCM of 404 & 96 is 9696

therefore, HCF of 404 & 96 is 2×2=4

product of two given numbers= 38784

Hence, HCF×LCM=product of two given numbers

hope it helps you.

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