find the HCF and LCM of 510 and 102 and verify that HCF ×LCM =Products of two given numbers.
Answers
Answer:
First taking out HCF of both numbers :-
HCF of 510 ----------
Factors of 510 = 2 × 3 × 5 × 17
HCF of 102 ----------
Factors of 102 = 2 × 3 × 17
So ,
Factors of 510 => 2 × 3 × 5 × 17
Factors of 102 => 2 × 3 × 17
Common => 2 × 3 × 17 = ? ( HCF )
= 6 × 17
= 102 ( HCF )
Now , Find the LCM of both numbers :-
LCM of 510 -------
Factors of 510 = 2 × 3 × 5 × 17
LCM of 102 --------
Factors of 102 = 2 × 3 × 17
So ,
Factors of 510 => 2 × 3 × 5 × 17
Factors of 102 => 2 × 3 × 17
Common = 2 × 3 × 17 × 5
= 6 × 17 × 5
= 102 × 5
= 510 ( LCM )
Verification :-
Put all the values which are given ----
HCF × LCM = Product of two numbers
102 × 510 = 102 × 510
Hence , verified .
Hope it will help !