find the HCF and LCM of 6,72,120 using prime factorisation
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Step-by-step explanation:
We have : 6=2×3,72=2
3
×3
2
,120=2
3
×3×5
Here, 2
1
and 3
1
are the smallest powers of the common factors 2 and 3 respectively.
So, HCF(6,72,120)=2
1
×3
1
=2×3=6
2
3
,3
2
and 5
1
, are the greatest powers of the prime factors 2,3 and 5 respectively involved in the three numbers.
So, LCM(6,72,120)=2
3
×3
2
×5
1
=360
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