Question

find the hcf and lcm of 6(x²-3 x+2) and 18(x²-4 x+3)​

Answer 1

Answer:

x

2

−3x+2=x

2

−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x

2

−4x+3=x

2

−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)