Question

Find the HCF and LCM of 60,,84,108 using prime factorization method

Answer 1

60=2*2*3*5
84 =2*2*3*7
108=2*2*3*3*3
Hcf(60,84,108)=2*2*3=12
Lcm=2*2*3*5*7*3*3(multiply and write the product)

Answer 2

HCF of 60 , 84 , 108 is 12 and LCM of 60 , 84 , 108 is 3780

Given :

The numbers 60 , 84 , 108

To find :

The HCF and LCM of the numbers

Concept :

HCF :

For the given two or more numbers HCF is the greatest number that divides each of the numbers

LCM :

For the given two or more numbers LCM is the least number which is exactly divisible by each of the given numbers

Solution :

Step 1 of 4 :

Write down the given numbers

The given numbers are 60 , 84 , 108

Step 2 of 4 :

Prime factorise the given numbers

60 = 2 × 2 × 3 × 5

84 = 2 × 2 × 3 × 7

108 = 2 × 2 × 3 × 3 × 3

Step 3 of 4 :

Find HCF

The required HCF

= 2 × 2 × 3

= 12

Step 4 of 4 :

Find LCM

Hence the required LCM

= 2 × 2 × 3 × 3 × 3 × 5 × 7

= 3780

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If HCF of two numbers be 40 then which of the following cannot be their LCM.

https://brainly.in/question/28609013

2. The HCF and LCM of two numbers are 17 & 1666 respectively. if one of the numbers is 119 find the other

https://brainly.in/question/13812250