Math, asked by Anonymous, 1 year ago

find the hcf and lcm of (a²b³c5d) and (a³bc³)


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Answers

Answered by atithisharma2
2
hey here is ur answer


a²b³c^5d
=a×a×b×b×b×c×c×c×c×c×d

a³bc³=a×a×b×c×c×c

so h.c.f =a²bc³

and l.c.m=a²bc³×a×b×b×c×c×d
=a³b³c^5d

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Answered by manishranjan1
0
hcf a2bc3
lcm a3b3c5d
is the answer
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