find the hcf and lcm of (a²b³c5d) and (a³bc³)
sohaib4:
hi!
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Answered by
2
hey here is ur answer
a²b³c^5d
=a×a×b×b×b×c×c×c×c×c×d
a³bc³=a×a×b×c×c×c
so h.c.f =a²bc³
and l.c.m=a²bc³×a×b×b×c×c×d
=a³b³c^5d
a²b³c^5d
=a×a×b×b×b×c×c×c×c×c×d
a³bc³=a×a×b×c×c×c
so h.c.f =a²bc³
and l.c.m=a²bc³×a×b×b×c×c×d
=a³b³c^5d
Answered by
0
hcf a2bc3
lcm a3b3c5d
is the answer
lcm a3b3c5d
is the answer
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