Question

Find the HCF and LCM of P(x) = x - 27 and Q(x) = x2 - 4x +3.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Find the HCF and LCM of P(x) = x - 27 and Q(x) = x2 - 4x +3.​

Step-by-step explanation:

p(x)=x-27

     =x-3*3*3

q(x)=x2 - 4x +3

     =(x-1)(x-3)

GCD=(x−3)

LCM=(x−3)

The HCF and LCM of (P(x) = x - 27 and Q(x) = x2 - 4x +3.) = 1​ because there is no common factors.

If the question is Find the HCF and LCM of P(x) = x3 - 27 and Q(x) = x2 - 4x +3.

Step-by-step explanation:

p(x)=x3-27

     =(x−3)(x2+3x+9)

q(x)=x2 - 4x +3

     =(x-1)(x-3)

GCD=(x−3)

LCM=(x−3)