Question

find the HCF and LCM of pair of integers (510,92) and verify whether product of two numbers of pair=HCF*LCM

Answer 1

510=2×3×5×17
92=2×2×23
hcf (510,92) product of smallest power of each common prime factor in the no.=2
Lcm (510,92)= product of greatest power in each prime factor =2×2×3×5×17×23=233460
Lcm (510,92)×Hcf (510,92)
23460×2=46920
510×92=46920