Question

-
Find the HCF and LCM
of the 2(x²-16)and(x+4)​

Answer 1

$2( {x}^{2} - 16) = 2( {x}^{2} - {4}^{2}) \\ \\ = > 2(x - 4)(x + 4)$

So, the H. C. F. = (x+4) and

L. C. M. :

$2( {x}^{2} - 16)$