Find the HCF and LCM of the following f(x)=2x²-5x²=3x and g(x)=x⁴-27x
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Answer:
Let f(x)=x
4
+3x
3
+5x
2
+26x and g(x)=x
4
+2x
3
−4x
2
−x+28
Given that GCD =x
2
+5x+7. Also, we have GCD × LCM= f(x) × g(x).
Thus, LCM=
GCD
f(x)×g(x)
Now, GCD divides both f(x) and g(x).
Let us divided f(X) by the GCD.
When f(x) is divided by GCD, we get the quoteint as x
2
−2x+8.
Now, (1) → LCM =(x
2
−2x+8)×g(x)
Thus, LCM =(x
2
−2x+8)(x
4
+2x
3
−4x
2
−x+28).
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