find the HCF and LCM of the following given pairs of numbers by prime factorisation 1) 120;90
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Answer:
23 is the correct answer
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Answer:
(1) 120, 90
120⇒2×2×2×3×5=23×3×5
90⇒2×3×3×5=2×32×5
HCF⇒2×3×5=30
L.CM⇒23×32×5=360
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