Question

Find the HCF and LCM of the following integers by applying prime factorization. 1. 12, 15 and 21.

Answer 1

Answer:

HCF=1

LCM=420

Step-by-step explanation:

1=1×1

12=2×2×3×1

15=3×5×1

21=3×7×1

HCF=Common factor=1

LCM=2×2×3×5×7=420

Answer 2

Answer:

Heya dude...................... ❤

12 = 2 *2*3

= 2^2 *3^1

15 = 3*5

21= 3*7

Hence,

H.C.F = Product of smallest power of eaxh common prime factor = 3 = 3^1

L.CM = Product of greatest power of each factor = 2^2 *3*5*7

= 4*3*5*7

= 420

Hope it’s helpful...... ☆(❁‿❁)☆