Question

find the HCF and LCM of the following numbers by using prime factorization 1) 8 9 and 2) 12 ,15 and 21​

Answer 1

Answer:

8=2×2×2×1

9=3×3×1

Therefore HCF of 8 & 9=1

LCM of 8 & 9=2×2×2×3×3=72

Again,

12=2×2×3

15=3×5

21=3×7

Therefore HCF of 12,15 & 21=3

LCM of 12,15 & 21=2×2×3×5×7

=420

Answer 2

Answer:

8 and 9= 2×2×2×3×3 (LCM)

HCF =1

12 , 15 and 21=3×2×3×5×7 (LCM)

HCF = 3