Find the HCF and LCM of the following pairs of integers and verify that LCM×HCF =product of the two numbers: 45 and 165
Answers
Answer :-
HCF & LCM = 495 & 15 respectively.
- Two numbers = 45, 165
- HCF & LCM and verify : LCM × HCF = Product of numbers.
Here, the numbers are 45 & 165
We will find LCM by prime factorization:-
Now finding HCF by prime factorization:-
Therefore,
LCM & HCF : 495 & 15 respectively.
→ HCF × LCM = Product of numbers
→ 495 × 15 = 45 × 165
→ 7425 = 7425
Solution :-
Given 2 Numbers are 45 & 165.
Prime Factors of Both Numbers :-
→ 45 = 3 * 3 * 5 = 3² * 5
→ 165 = 3 * 5 * 11
So,
→ HCF = 3 * 5 = 15 .
→ LCM = 3² * 5 * 11 = 9 * 5 * 11 = 495.
Verification :-
→ LCM×HCF = product of the two numbers.
Taking LHS,
→ LCM × HCF
→ 495 * 15
→ 7425 ---------------- Equation (1).
Taking RHS,
→ product of the two numbers
→ 45 * 165
→ 7425 ---------------- Equation (2).
→ Equation (1) = Equation (2) .
→ LHS = RHS (Hence, Verified).
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★★Extra Brainly Knowledge★★
✯✯ Some Properties of HCF & LCM ✯✯
☛ HCF(Highest Common Factor) :- The largest or greatest factor common to any two or more given natural numbers is termed as HCF of given numbers. Also known as GCD (Greatest Common Divisor).
☛ LCM(Least Common Multiple) :- The least or smallest common multiple of any two or more given natural numbers are termed as LCM.
☛ The H.C.F. of given numbers is not greater than any of the numbers.
☛ The L.C.M. of given numbers is not less than any of the given numbers.
☛ The H.C.F. of two co-prime numbers is 1.
☛ The L.C.M. of two or more co-prime numbers is equal to their product.
☛ If a number, say x, is a factor of another number, say y, then the H.C.F. of x and y is x and their L.C.M. is y.
☛ The product of the H.C.F. and the L.C.M. of two numbers is equal to the product of the given numbers. That is, if a and b are two numbers, then a x b = H.C.F. x L.C.M.
☛ LCM of fractions = ( LCM of Numerators ) / ( HCF of Denominators ) .
☛ HCM of fractions = ( HCM of Numerators ) / ( LCF of Denominators ) .