Math, asked by suhasdmestry, 9 months ago

Find the HCF and LCM of the numbers given below. Verify that their product is
equal to the product of the given numbers,
(i) 32, 37 (ii) 46, 51 (iii) 15, 60 (iv) 18, 63 (v) 78, 104​

Answers

Answered by Sreyashpedia
13

Answer:

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Answered by 6aanushkapalveyhs
1

1 .  32 = 2 x 16

= 2 x 2 x 8

= 2 x 2 x 2 x 4

= 2 x 2 x 2 x 2 x 2 x 1

37 = 37 x 1

∴ HCF of 32 and 37 =1

LCM of 32 and 37 = 2 x 2 x 2 x 2 x 2 x 37

= 1184

HCF x LCM = 1 x 1184

= 1184

Product of the given numbers = 32 x 37

= 1184

∴ HCF x LCM = Product of the given numbers.                                                  ii. 46 = 2 x 23 x 1

51 = 3 x 17 x 1

∴ HCF of 46 and 51 = 1

LCM of 46 and 51 = 2 x 23 x 3 x 17

= 2346

HCF x LCM = 1 x 2346

= 2346

Product of the given numbers = 46 x 51

= 2346

∴ HCF x LCM = Product of the given numbers.

iii. 15 = 3 x 5

60 = 2 x 30

= 2 x 2 x 15

= 2 x 2 x 3 x 5

∴ HCF of 15 and 60 = 3 x 5

= 15

LCM of 15 and 60 = 3 x 5 x 2 x 2

= 60

HCF x LCM = 15 x 60

= 900

Product of the given numbers = 15 x 60

= 900

∴ HCF x LCM = Product of the given numbers.                                                 iv. 18 = 2 x 9

= 2 x 3 x 3

63 = 3 x 21

= 3 x 3 x 7

∴ HCF of 18 and 63 = 3 x 3

= 9

LCM of 18 and 63 = 3 x 3 x 2 x 7

= 126

HCF x LCM = 9 x 126

= 1134

Product of the given numbers = 18 x 63

= 1134v. 78 = 2 x 39

= 2 x 3 x 13

104 = 2 x 52

= 2 x 2 x 26

= 2 x 2 x 2 x 13

∴ HCF of 78 and 104 = 2 x 13

= 26

LCM of 78 and 104 = 2 x 13 x 3 x 2 x 2

= 312

HCF x LCM = 26 x 312

= 8112

Product of the given numbers = 78 x 104

= 8112

∴ HCF x LCM = Product of the given numbers.

∴ HCF x LCM = Product of the given numbers.                                                   I hope it is right  .                                

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