Question

find the hcf and lcm of the numbers given below. verify that their product is equal to the product of given numbers with method 46,51

Answer 1

lets us find the least common multiple of 46,51
2 |46,51
3 |23,51
|23,17 So L.C.M of 46 and 51 is 2×3×23×17=> 6×391
=> 2346 46=2×23=1×46 and 51=3×17=1×51 So factors of 46 are1,46,2,23 and factors of 51 are 1,51,17,3 . Now find Highest Common Factor by Euclid division method .
46√51 | 1
-46
________
5√46 | 9
-45
____________
1√5 | 5
-5
______________
0. So 1 is the H.C.F of 46 and 51 hence product of 46 and 51 is 51*46=2346 . H.C.F.×L.C.M.
=46(51)=2346. Hence proved .Hope I helps you... Mark me as Brainliest.

Answer 2

Answer:

the question is . Find the HCF and LCM of 46 and 51 ?

Step-by-step explanation:

2 | 46 3 | 51

23 | 23 17 | 17

| 1 | 1

HCF = 1 .

LCM = 2×23×3×17 = 2,346 .

HCF × LCM = 1×2,346 = 2,346

Product of the two given numbers = 46×51 = 2,346 .

Product of the two given numbers = HCF × LCM .