Question

find the. hcf and LCM of two numbers is 2000 and one of two numbers is 50 find the second number​

Answer 1

Let the other number be

Let the other number be ′

Let the other number be ′ x

Let the other number be ′ x ′

Let the other number be ′ x ′

Let the other number be ′ x ′ Given:LCM+HCF=600

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x=

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x= 280

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x= 28040×560

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x= 28040×560

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x= 28040×560

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x= 28040×560 ⇒x=40×2

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x= 28040×560 ⇒x=40×2⇒x=80

Let the other number be ′ x ′ Given:LCM+HCF=600⇒14HCF+HCF=600⇒15HCF=600⇒HCF=40⇒LCM=14×40=560Since HCFxLCM=Product of 2 numbers=>40×560 = 280×x⇒x= 28040×560 ⇒x=40×2⇒x=80hence the other number is 80