find the HCF and LCM. x²-5x+6,2x²-8 and (x-2)² can any body solve ittt
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Let u(x) = 2x2 – 8
On factorizing the above equation,
u(x) = 2(x2 – 4)
Let v(x) = x2 – 5x + 6
On factorizing the above equation,
Sum = -5
Product = 6
Therefore the two numbers satisfying the above conditions are -2 and -3.
v(x) = x2 – 3x – 2x + 6
v(x) = x(x – 3) - 2(x – 3)
v(x) = (x – 2) (x – 3)
By comparing u(x) and v(x),
LCM = 2(x2 – 4) (x – 3)
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