find the hcf by division algorithm of the number 1305,1365,1530
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hcf of 1305 & 1365
a= bq+r
1365 =1305×1 +60
1305=60×21+45
60=45×1+15
45=15×3+0
Hcf=15
hcf of 15 & 1530
1530=15×102+0
Hence hcf is 15..
a= bq+r
1365 =1305×1 +60
1305=60×21+45
60=45×1+15
45=15×3+0
Hcf=15
hcf of 15 & 1530
1530=15×102+0
Hence hcf is 15..
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