Question

find the HCF by division method and reduce to the simplest form 492
​

Answer 1

Answer:

We have to find the HCF of 248 and 492. Let us use the prime factorization method. Firstly, we have to write each number as a product of its prime factors. Let us consider 248. We can write 248 in its prime factorization form as

248=23×31

Now let us consider 492.

492=22×3×41

Now, we have to list the common factors of both the numbers.

Common factors of 248 and 492 are 22 .

The product of all common prime factors is the HCF. We have to use the lower power of each common factor.

Therefore, HCF of 248 and 492 is 22=2×2=4

Answer 2

$\sf\huge\red{Answer:)}$

$248 \: = {2}^{3} \times 31 \\ 492 = {2}^{2} \times 3 \times 41 \\ HCF\: is \: 4$

[/tex]