Question

find the hcf by Euclid division algorithm of the number 92690,7378​

Answer 1

Here is ur Answer mate:-

Step-by-step explanation:

By Euclid’s division algorithm, 

92690 = 7378 x 12 + 4154 

7378 = 4154 x 1+ 3224 

4154 = 3224 x 1 + 930 

3224 = 930 x 3 + 434 

930 = 434 x 2 + 62 

434 = 62 x 7 + 0 

Therefore, HCF (92690, 7378) = 62 

Hope it helps you

Thanks...

Answer 2

$\bf{\underline{\underline{Question}}}$

Find the HCF by Euclid division algorithm of the number 92690,7378.

$\bf{\underline{\underline{Solution}}}$

$\sf{Finding\:HCF\:by\:Euclid\:Division\:Method}$

$\bf{92690\:=\:7378 \times12\:+\:4154}$

$\bf{7378\:=\:4154 \times1 \:+\:3224}$

$\bf{4154\:=\:3224 \times1 \:+\:930}$

$\bf{3224\:=\:930 \times3 \:+\:434}$

$\bf{930\:=\:434 \times2 \:+\:62}$

$\bf{434\:=\:62 \times7 \:+\:0}$

Therefore,

$\sf</strong><strong>{</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong>{\:HCF\:by\:of\:(92690,7378)\:will\:be\:62}</strong><strong>}</strong><strong>$

$\bf{\underline{\underline{Thanks}}}$