Question

Find the HCF by factorization method
i. 384, 432, 1200
ii. 5610, 10465​

Answer 1

Answer:

Ans down

Step-by-step explanation:

1)let a= 432

and b =384

by EDL,

432= 384x1+48

384 48×8+0

HCF(384,432)=48

now let d=1200

and c=48

by EDL,

d=cq+r

1200=48x25+0

thus, HCF(384,432,1200)=48

2)Given : 5610 and 10465.

To find : HCF.

Solution:

HCF of 5610 and 10465 = 5.