find the HCF by long division method of 420 and 360
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LLO
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120 allu JOU.
2
14,
7,
Now, the HCF of 420 and 360 = 60
So, the required size of the slab must be 60 cm x 60 cm.
Area of the floor
Hence, the number of slabs required
Area of one slab
420 x 360
60 x 60
-
= 42
Thus, the required number of marble slabs is 42.
se 3.3
8, 27
the HCF of the following set of the numbers by listing factors method:
b) 24, 32
c) 12,30
d) 27, 54, 45
che HCF of the following set of the numbers by prime factorisation method:
04, 180
b) 225, 375
c) 524, 128, 56 d) 88, 64, 90, 30
he HCF of the following set of the numbers by long division method:
5, 625
b) 224, 1500, 1440 c) 422, 345
d) 110, 770, 1331
e HCF of the following set of the numbers by short division method:
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