Find the HCF for the following
24 , 72,48
With steps
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24=2×12
72=2×12×3
48=2×12×2
SO, 2 AND 12 ARE COMMON IN ALL FACTORS
THEN 24 (2×12) IS HCF OF ALL THE NO.
72=2×12×3
48=2×12×2
SO, 2 AND 12 ARE COMMON IN ALL FACTORS
THEN 24 (2×12) IS HCF OF ALL THE NO.
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