Math, asked by iwnwism, 4 days ago

find the hcf nd lcm of 20 and 36. verify that hcf x lcm= product of two numbers​

Answers

Answered by saitanmayi02
0

Answer:

Step-by-step explanation:

Let a=404 and b=96

Expressing the number as a product of prime number

404=2×2×101

96=2×2×2×2×2×3

∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696

∴ HCF of 404 and 96 is 2×2=4

Now HCF×LCM=4×9696=38784

Product of two given numbers 404×96=38784

Hence HCM×LCM= product of two given numbers.

Answered by krishpmlak
0

Answer:

Step-by-step explanation:

hcf and lcm of 20 and 36

Prime factors of 20 = 2 × 2 × 5

Prime factors of 36 = 2 × 2 × 3 × 3

hcf of (20,36) = 2 × 2 = 4 (∵ common factors of 20 and 36 )

lcm of (20 ,36) = 2 × 2 × 3 × 3 × 5 =180 (∵ common factors of 20,36 and product of remaining factors of 20 ,36 )

Verification :

hcf × lam = Product of two numbers

4 × 180 = 20 × 36

720 = 720

∴ verified that,hcf × lcm= product of two numbers.

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