find the hcf nd lcm of 20 and 36. verify that hcf x lcm= product of two numbers
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Answered by
0
Answer:
Step-by-step explanation:
Let a=404 and b=96
Expressing the number as a product of prime number
404=2×2×101
96=2×2×2×2×2×3
∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696
∴ HCF of 404 and 96 is 2×2=4
Now HCF×LCM=4×9696=38784
Product of two given numbers 404×96=38784
Hence HCM×LCM= product of two given numbers.
Answered by
0
Answer:
Step-by-step explanation:
hcf and lcm of 20 and 36
Prime factors of 20 = 2 × 2 × 5
Prime factors of 36 = 2 × 2 × 3 × 3
hcf of (20,36) = 2 × 2 = 4 (∵ common factors of 20 and 36 )
lcm of (20 ,36) = 2 × 2 × 3 × 3 × 5 =180 (∵ common factors of 20,36 and product of remaining factors of 20 ,36 )
Verification :
hcf × lam = Product of two numbers
4 × 180 = 20 × 36
720 = 720
∴ verified that,hcf × lcm= product of two numbers.
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