find the hcf of 1)x4-2x2+1 and x4-2x2+2x3+2x-1
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x2 + 2x – 15 & x2 – 7x + 12 = x2 + 5x – 3x – 15 = x2 – 4x – 3x – 12 = x (x + 5) – 3 (x + 5) = x (x – 4) – 3 (x – 4) =(x + 5) (x – 3) = (x – 4) (x – 3) HCF = (x – 3)
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