Find the HCF of 10 ab , 20 bc. a) 10 a b) 10 b c) 10 d) 20
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10ab = 2*5*a*b
20bc = 2*2*5*b*c
So, the common factors are 2,5,b
So the HCF is 2*5*b = 10b
Your answer is option b) 10b
I hope this helped!
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