Math, asked by km035181, 2 days ago

Find the HCF of 10 ab , 20 bc. a) 10 a b) 10 b c) 10 d) 20​

Answers

Answered by Equuleus
0

10ab = 2*5*a*b
20bc = 2*2*5*b*c

So, the common factors are 2,5,b
So the HCF is 2*5*b = 10b

Your answer is option b) 10b

I hope this helped!

Similar questions