Question

Find the hcf of 10216 and 828 by Lemma class 10 cbse board​

Answer 1

Step-by-step explanation:

using Euclids division lemma.

a=bq+r; 0<_ r<b.

here a=10216 and b=828

so, 10216=828× 12+280

828=280×2+268

280=268×1+12

268=12×22+4

12=4×3+0.

HCF is 4.

I hope you got it ..

it's simple.....