find the HCF of 112,210 and 252 by prime factorisation method and please do it in paper and then send the step by step solution and answer then I will mark you as brainlist
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112= 2×2×2×2×7
210= 2×5×3×7
252= 2×2×3×3×7
So, 2 and 7 are common factors in the given numbers
So, H.C.F(Highest Common Factor) of the given numbers is
= 2×7
= 14
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