find the hcf of 120 and 200 by Euclid division lemma
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Set up a division problem where a is larger than b.
a ÷ b = c with remainder R. Do the division. Then replace a with b, replace b with R and repeat the division. Continue the process until R = 0.
200 ÷ 120 = 1 R 80 (200 = 1 × 120 + 80)
120 ÷ 80 = 1 R 40 (120 = 1 × 80 + 40)
80 ÷ 40 = 2 R 0 (80 = 2 × 40 + 0)
When remainder R = 0, the GCF is the divisor, b, in the last equation. GCF = 40
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