Question

find the hcf of 120 and 448 and represent it in the form of 120m+448m

Answer 1

Answer:

m=15 and n=[-4]

Explanation:

448=120*3+88

120=88*1+32

88=32*2+24

32=24*1+8

24=8*3+0

So HCF is 8.

8=32-24

8=32-88+32*2

8=(120-88)3-88

8=120(3)-88(4)

8=123(3)-[448-120(3)]{4}

8=120(3)-448(4)+120(12)

8=120(15)-448(4)

Take m=15 and n=[-4]

8=120m+488n