Find the HCF of 124,286 by Euclid's Division Lemma
Answers
Answer:
2
Step-by-step explanation:
Set up a division problem where a is larger than b.
a ÷ b = c with remainder R. Do the division. Then replace a with b, replace b with R and repeat the division. Continue the process until R = 0.
286 ÷ 124 = 2 R 38 (286 = 2 × 124 + 38)
124 ÷ 38 = 3 R 10 (124 = 3 × 38 + 10)
38 ÷ 10 = 3 R 8 (38 = 3 × 10 + 8)
10 ÷ 8 = 1 R 2 (10 = 1 × 8 + 2)
8 ÷ 2 = 4 R 0 (8 = 4 × 2 + 0)
When remainder R = 0, the HCF is the divisor, b, in the last equation. HCF = 2
Answer:
Euclid's division lemma :
Let a and b be any two positive Integers .
Then there exist two unique whole numbers q and r such that
a = bq + r ,
0 ≤ r <b
Now ,
Clearly, 286 > 124
Start with a larger integer , that is 286.
Applying the Euclid's division lemma to 286 and 184, we get
286 = 2 × 124 + 38
Since the remainder 38 ≠ 0, we apply the Euclid's division lemma to divisor 124 and remainder 38 to get
124 = 3 × 38 + 10
We consider the new divisor 38 and remainder 10 and apply the division lemma to get
38 = 3 × 10 + 8
We consider the new divisor 10 and remainder 8 and apply the division lemma to get
10 = 1 × 8 + 2
We consider the new divisor 8 and remainder 2 and apply the division lemma to get
8 = 4 × 2 + 0
Now, the remainder at this stage is 0.
So, the divisor at this stage, ie, 4 is the HCF of 286 and 124.