Question

find the HCF of 12576 and 4052 by using the fundamental Theorem of arithmetic.Hence find the LCM of the numbers

Answer 1

Answer:

4052=2×2×1013

12576=2×2×2×2×2×3×131

The HCF of 4052,12576 is: 2×2=4

Answer 2

$Given \: numbers \: 12576 \:and \: 4052$

$We \:have$

$12576 = 2 \times 2\times \times 2 \times 2 \times 3\times 131 = 2^{5} \times 3^{1} \times 131^{1}$

$4052 = 2 \times 2\times 1013 = 2^{2} \times 1013^{1}$

$HCF ( 12576 , 4052 ) = 2^{2} = 4$

$\blue {( Product \:of \:the \: smallest \:power}$

$\blue {of \:each \: Common \:prime \: factors}$

$\blue { of \: numbers )}$

Therefore.,

$\red{HCF ( 12576 , 4052 ) }\green { = 4}$

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