find the hcf of 1260 and 7344 by euclids division algorithem
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3
the hcf of 1260 is 1260/2=630,
630/2=315,
315/3=15,
15/3=5,
5/5=12*2*3*3*5
=2*3*5=30
the hcf of 7344 is also similar like this you have to just do square root of 7344 which is 85.6 and that is not equal to zero
630/2=315,
315/3=15,
15/3=5,
5/5=12*2*3*3*5
=2*3*5=30
the hcf of 7344 is also similar like this you have to just do square root of 7344 which is 85.6 and that is not equal to zero
Answered by
7
Answer:
HCF of 1260 and 7344 is 36.
Step-by-step explanation:
Given : Number 1260 and 7344.
To find : The HCF of 1260 and 7344 by Euclid division algorithm ?
Solution :
Euclid division algorithm states that,
In the relation a = bq + r, where 0 ≤ r < b is a statement of the long division of number a by number b in which q is the quotient obtained and r is the remainder.
So, We divide 7344 by 1260
Now, The remainder becomes 0.
Therefore, HCF of 1260 and 7344 is 36.
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