find the HCF of 1260 and 7344 using euclids division algorithm
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Answered by
207
a=bq+r
7344=1260×5+1044
1260=1044×1+216
1044=216×4+180
216=180×1+36
180=36×5+0
7344=1260×5+1044
1260=1044×1+216
1044=216×4+180
216=180×1+36
180=36×5+0
Answered by
97
Answer: The HCF of 1260 and 7344 is 36.
Step-by-step explanation:
In euclids division algorithm,
We will follow the following steps,
Step 1 : divide 7344 by 1260,
Quotient = 5 remainder = 1044,
Step 2: divide divisor 1260 by remainder,
Quotient = 1 remainder = 216,
Step 3: Repeat the above steps until we get remainder 0.
Thus, the last quotient which gives the remainder zero is 36.
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