Question

Find the hcf of: 12x (x²+1) and 18 (x²+1

Answer 1

Answer:

12x (x2 + 1) = 3*2*2*x²+1

18(x2+1) .. = 3*3*2(x²+1)

so HCF =3*X²+1*2

=5(x²+1)