find the hcf of 136,170,255 by euclids algorithm
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136 = 2^3 × 17
170 = 2 × 5 ×17
255 = 3 × 5 × 17
HCF( 136,170,255) = 17
170 = 2 × 5 ×17
255 = 3 × 5 × 17
HCF( 136,170,255) = 17
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