find the HCF of 136 and 208 and express it in the form 136q + 208r.
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Applying division lemma to 117 and 52, we get
117=52×2+13...........(i)
52=13×4+0
∴8 is the HCF of 52 and 117
From (i), we have
13=52(−2)+117(1)
Hence it is expressed in the form of 52x+117y
By comparing, we get x=−2,y=1
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super find the hcf of 136 and express
1363+2084
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