Question

find the hcf of 136and208 and express it in the form 136q +208r​

Answer 1

Answer:

Step-by-step explanation:

ANSWER

Applying division lemma to 117 and 52, we get

117=52×2+13...........(i)

52=13×4+0

∴8 is the HCF of 52 and 117

From (i), we have

13=52(−2)+117(1)

Hence it is expressed in the form of 52x+117y

By comparing, we get x=−2,y=1

Answer 2

Answer:

H.C.F of 136 and 208 is 2×2×2= 8