Question

Find the hcf of 136and208 and express it in the form 136q +208r​

Answer 1

Answer:

HCF of 117 and 65,

117= 65*1 +52

62= 52*1+13

here remainder becomes 0.

Therefore HCF of 65 and 117 is 13

HCF 13 can be expressed in the following form,

659(2)+117(-1)= 13

==> 130-117= 13

So value of x is 2 and value of y is -1

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Answer 2

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IMrGauravI

Applying division lemma to 117 and 52, we get

117=52×2+13...........(i)

52=13×4+0

∴8 is the HCF of 52 and 117

From (i), we have

13=52(−2)+117(1)

Hence it is expressed in the form of 52x+117y

By comparing, we get x=−2,y=1