Question

Find the HCF of 143 and 481. Also find two integers m and n such that
P = 143m + 481n
(P = HCF)
The HCF is 13, plz answer the other part.

Answer 1

Answer:

Step-by-step explanation:

Given:

H.C.F of 143 and 481 is 143m + 481n

The highest common factors among the given numbers are defined as the HCF of that numbers.

Calculation:

Using factorization, HCF can be found as

143 = 11 × 13

481 = 37 × 13

HCF = 13

The given HCF 143m + 481n

So equating both HCF, we get as

143 m + 481n = 13

⇒ 13 (11m + 37n ) = 13

⇒ (11m + 37n ) = 1     ---(i)

Now substituting all values, the options that satisfies the above equation will be the final answer.

Using option 3 as (-10, 3)

m = -10

n = -3

From equation (i)

11 × (-10) + 37 × (-3) = 1, which satisfies.

So, final answer is  -10, 3

Answer 2

Step-by-step explanation:

see the attachment for answers