Question

Find the HCF of 148, 272, 388 by long division method.
Anyone pls tell??

Answer 1

Answer:

The remainder has now become zero, so procedure stops. Since the divisor at this stage is 4, the HCF of 12576 and 4052 is 4.

Step-by-step explanation:

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Answer 2

$\large \bold{ \underline{ \underline{ \sf \: Answer : \: \: \: }}}$

→ HCF of 272 and 148 is 4

$\large \bold{ \underline{ \underline{ \sf \: Explaination : \: \: \: }}}$

$\large\pink{\textsf{ By using prime factoraisation method :}}$

→ 272 = 2 × 2 × 2 × 2 × 17

→ 148 = 2 × 2 × 37

Therefore ,

HCF ( 272 , 148 ) = 2 × 2 = 4

$\large\pink{\textsf{By using Euclid's algorithm :}}$

→ Since , 272 > 148 , we apply the division lemma to 272 and 148 , to get

272 = 148 × 1 + 124

→ Since the remainder 124 ≠ 0 , we apply the division lemma to 148 and 124 , to get

148 = 124 × 1 + 24

→ We consider the new divisor 124 and the new remainder 24 , and apply the division lemma to get

124 = 24 × 5 + 4

→ We consider the new divisor 24 and the new remainder 4 , and apply the division lemma to get

24 = 4 × 6 + 0

→ The remainder has now become zero , so our procedure stops , since the divisor at this stage is 4 , the HCF of 272 and 148 is 4