Question

Find the HCF of 1485and 4356 by Euclid division lemma

Answer 1

Answer:

Given numbers are 1485 and 4356.

The prime factorization of 1485 and 4356 gives:

Here, 32× 11 is the smallest power of the common factors 3 and 11.

Therefore, the H.C.F of these two integers = 3 × 3 × 11 = 99

22 × 33× 51 × 112 are the greatest powers of the prime factors 2, 3 and 7 respectively involved in the given numbers.

Now, L.C.M of 1485 and 4356 = 2 × 2 × 3 × 3 × 3 × 5 × 11 × 11 = 65430

Step-by-step explanation:

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Answer 2

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