Question

Find the HCF of 15,90,105 by prime factorisation
its ergent pleasee give the answer fast ​

Answer 1

H.c.f of 15,90,105 is 15

15 = 3,5

90 = 3,3,5,2

105 = 3,5,7

H.C.F = 3×5 = 15

Answer 2

Answer:

first you will find the HCF of 650, 350and 750

by any method but you have told by prime factorisation method

650 = 2 × 5 × 5 × 13

750 = 2 × 3 × 5 × 5 × 5

350 = 2•52•7.

= 2×175

= 5×35=. 2×5×7×5{ in simple words)

~so the common factor of that no are 2×5×5

=50 Greatest no which divide 650 350 750

Now you have told 15 ,90.105

HCF

Pf of 15 = 3×5

pf of 90= 2 × 3 × 3 × 5

of

pf of 105 = 3×5×7

common factor 3×5

= 15

so the greatest no which divide 15,90,105