find the hcf of 16 and 27
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the hcf of 16 and 27 by euclid's division lemma,
27=16×1+11
16=11×1+5
11=5×2+1
5=1×5+0
here the remainder is 0,
hence the hcf is 1
27=16×1+11
16=11×1+5
11=5×2+1
5=1×5+0
here the remainder is 0,
hence the hcf is 1
Similar questions
16=11×1+5
11=5×2+1
5=1×5+0
here the remainder is 0,